(x+4)x^2-(x+4)y^2=0

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Solution for (x+4)x^2-(x+4)y^2=0 equation: 


Simplifying
(x + 4) * x2 + -1(x + 4) * y2 = 0

Reorder the terms:
(4 + x) * x2 + -1(x + 4) * y2 = 0

Reorder the terms for easier multiplication:
x2(4 + x) + -1(x + 4) * y2 = 0
(4 * x2 + x * x2) + -1(x + 4) * y2 = 0
(4x2 + x3) + -1(x + 4) * y2 = 0

Reorder the terms:
4x2 + x3 + -1(4 + x) * y2 = 0

Reorder the terms for easier multiplication:
4x2 + x3 + -1y2(4 + x) = 0
4x2 + x3 + (4 * -1y2 + x * -1y2) = 0

Reorder the terms:
4x2 + x3 + (-1xy2 + -4y2) = 0
4x2 + x3 + (-1xy2 + -4y2) = 0

Reorder the terms:
-1xy2 + 4x2 + x3 + -4y2 = 0

Solving
-1xy2 + 4x2 + x3 + -4y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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